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It means that reading the disassembled code requires us to mentally map %rax not to the return value, but to just another scratch reg. (how do ax, ah, al map onto eax?) there are also 8 new. I just want to read values that are currently in those registers
Rax, rbx, rcx, rdx, rsp This is x64 assembly generated from gcc 4.8 compiling c++ code. Rbp, rsi, rdi and print them out, thats it.
In at&t syntax, the instruction
Mov (%rax), %eax # at&t syntax or, equivalently in intel syntax Mov eax, dword ptr [rax] Essentially all x86 chips released in the last decade from amd and intel support this isa I am struggling on a homework because i do not understand what these lines are supposed to mean
Thus (%rax) means to get the value of the pointer currently stored in %rax What does the star decoration do on that Does that further dereference that value (thus (%rax) is itself a pointer) I'm having trouble googling *( assembly syntax
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