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5 mins would be appropriate unless you are expressing it as an adjective then use the singular form, as in a five minute break or the ten minute mark English pronunciation practice can be a challenging part of learning a new language, but our exercises and printables can help make practicing fun! It might therefore not be considered wrong to use singular forms of abbreviations with plural numbers.
No, $m:=\min\ {x,y\}$ is a random variable itself that records the lowest value of $x,y$ Properties of min (x,y) and max (x,y) operators ask question asked 5 years, 4 months ago modified 5 years, 4 months ago You do not compare the probabilities but the values of the random variables.
So yes, it's a function that, taken two elements, gives you the minimum of those.
But in my problem, there's an outer max layer The space between arg and min is confusing It would better be written argmin What the operator argmin does, when applied to a function, is pick out the point in the function's domain at which the function takes its minimum value (assuming that the point is unique)
In this case, arg minw, b maxα ≥ 0f(w, b, α) is that value of (w, b) which minimizes maxα ≥ 0f(w, b, α). What if the places are swapped, or some other combination Quadratic programming (convex optimization), linear programming, dynamic programming How does it differ from minimax?
I understand the basics of continuity and algebra of continuity of limits
So i add the picture of the proof such that it is in the book of real analysis.i would really appreciate if someone could explain it to me as simple as possible I'm struggling to understand it, what do $\min { [f,g]}$ and $\max { [f,g]}$ mean Please provide additional context, which ideally explains why the question is relevant to you and our community Some forms of context include
Background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc.
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