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I know that $\infty/\infty$ is not generally defined So new_infinity would just become 1 + infinity. However, if we have 2 equal infinities divided by each other, would it be 1
Infinity refers to something without any limit, and is a concept relevant in a number of fields, predominantly mathematics and physics My argument is that if $1 + \infty > \infty$ then there exists a number greater than $\infty$, disproving the concept of infinity, because you can't simply add $1$ to infinity, because infinity is ever increasing The english word infinity derives from latin infinitas, which can be translated as unboundedness , itself derived from the greek word apeiros, meaning endless .
Can this interpretation (subtract one infinity from another infinite quantity, that is twice large as the previous infinity) help us with things like $\lim_ {n\to\infty} (1+x/n)^n,$ or is it just a parlor trick for a much easier kind of limit?
In particular, infinity is the same thing as 1 over 0, so zero times infinity is the same thing as zero over zero, which is an indeterminate form Your title says something else than infinity times zero It says infinity to the zeroth power. Similarly, the reals and the complex numbers each exclude infinity, so arithmetic isn't defined for it
And then, you need to start thinking about arithmetic differently. Infinity plus infinity ask question asked 13 years, 8 months ago modified 7 months ago Infinity divided by infinity ask question asked 7 years, 11 months ago modified 7 years, 11 months ago I suppose these are the equations with infinity that are universally considered correct
∞ = ∞ ∞ + n = ∞ ∞ * n = ∞ n/∞ = 0 where n can be any possible value
These equations can be rearranged to. This $1^\infty$ (in regards to indeterminate forms) actually means When there is an expression that approaches 1 and then it is raised to the power of an expression that approaches infinity we can't determine what happens in that form But i can't disprove their points
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